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4-1.Newton's Laws of Motion
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द्रव्यमान $m$ के एक कण की गति, $y =u t+\frac{1}{2} g t^{2}$ से वर्णित है। उस कण पर लगने वाले बल को ज्ञात करो।
Option A
Option B
Option C
Option D
Solution
We know
$y=u t+\frac{1}{2} g t^{2}$
Now.
$v=\frac{ d y}{ d t}=u+g t$
acceleration, $a=\frac{ d v}{ d t}=g$
Then the force is given by $F=m a=m g$
Thus the given equation describes the motion of a particle under acceleration due to gravity and $y$ is the position coordinate in the direction of $g$
$y=u t+\frac{1}{2} g t^{2}$
Now.
$v=\frac{ d y}{ d t}=u+g t$
acceleration, $a=\frac{ d v}{ d t}=g$
Then the force is given by $F=m a=m g$
Thus the given equation describes the motion of a particle under acceleration due to gravity and $y$ is the position coordinate in the direction of $g$
Standard 11
Physics
