Motion of a particle of mass m is described by y=u t+frac{1}{2} g t^{2} . force acting on particle.

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4-1.Newton's Laws of Motion

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The motion of a particle of mass $m$ is described by $y=u t+\frac{1}{2} g t^{2} .$ Find the force acting on the particle.

Option A

Option B

Option C

Option D

Solution

We know
$y=u t+\frac{1}{2} g t^{2}$
Now.
$v=\frac{ d y}{ d t}=u+g t$
acceleration, $a=\frac{ d v}{ d t}=g$
Then the force is given by $F=m a=m g$
Thus the given equation describes the motion of a particle under acceleration due to gravity and $y$ is the position coordinate in the direction of $g$

Standard 11

Physics

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easy

The motion of a particle of mass $m$ is described by $y=u t+\frac{1}{2} g t^{2} .$ Find the force acting on the particle.

Solution

Similar Questions

A particle moves in $\mathrm{x}-\mathrm{y}$ plane under the influence of a force $\vec{F}$ such that its linear momentum is $\vec{P}(t)=\hat{i} \cos (k t)-\hat{j} \sin (k t)$. If $k$ is constant, the angle between $\overrightarrow{\mathrm{F}}$ and $\overrightarrow{\mathrm{P}}$ will be :

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