The negation of the compound statement $^ \sim p \vee \left( {p \vee \left( {^ \sim q} \right)} \right)$ is
The negation of the compound statement $^ \sim p \vee \left( {p \vee \left( {^ \sim q} \right)} \right)$ is
- A
$\left( {^ \sim p \wedge q} \right) \wedge p$
- B
$\left( {^ \sim p \wedge q} \right) \vee p$
- C
$\left( {^ \sim p \wedge q} \right){ \vee \,^ \sim }p$
- D
$\left( {^ \sim p{ \wedge ^ \sim }q} \right){ \wedge \,^ \sim }q$
Similar Questions
The logically equivalent of $p \Leftrightarrow q$ is :-
The logically equivalent of $p \Leftrightarrow q$ is :-
Consider the following two statements :
$P :$ lf $7$ is an odd number, then $7$ is divisible by $2.$
$Q :$ If $7$ is a prime number, then $7$ is an odd number.
lf $V_1$ is the truth value of the contrapositive of $P$ and $V_2$ is the truth value of contrapositive of $Q,$ then the ordered pair $(V_1, V_2)$ equals
Consider the following two statements :
$P :$ lf $7$ is an odd number, then $7$ is divisible by $2.$
$Q :$ If $7$ is a prime number, then $7$ is an odd number.
lf $V_1$ is the truth value of the contrapositive of $P$ and $V_2$ is the truth value of contrapositive of $Q,$ then the ordered pair $(V_1, V_2)$ equals
- [JEE MAIN 2016]
Which of the following statements is a tautology?
Which of the following statements is a tautology?
- [JEE MAIN 2022]
Negation of “Paris in France and London is in England” is
Negation of “Paris in France and London is in England” is
The statement $p → (p \leftrightarrow q)$ is logically equivalent to :-
The statement $p → (p \leftrightarrow q)$ is logically equivalent to :-