The number of elements in the set $\{x \in R :(|x|-3)|x+4|=6\}$ is equal to
$3$
$2$
$4$
$1$
$x \neq-4$
$(|x|-3)(|x+4|)=6$
$\Rightarrow \quad|x|-3=\frac{6}{|x+4|}$
No. of solutions $=2$
Examine whether the following statements are true or false :
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