The number of elements in the set $\{x \in R :(|x|-3)|x+4|=6\}$ is equal to
$3$
$2$
$4$
$1$
$x \neq-4$
$(|x|-3)(|x+4|)=6$
$\Rightarrow \quad|x|-3=\frac{6}{|x+4|}$
No. of solutions $=2$
Set $A$ has $m$ elements and Set $B$ has $n$ elements. If the total number of subsets of $A$ is $112$ more than the total number of subsets of $B$, then the value of $m \times n$ is
Let $S = \{ 0,\,1,\,5,\,4,\,7\} $. Then the total number of subsets of $S$ is
Write the following sets in the set-builder form :
$\{ 3,6,9,12\}$
State whether each of the following set is finite or infinite :
The set of lines which are parallel to the $x\,-$ axis
Are the following pair of sets equal ? Give reasons.
$A = \{ 2,3\} ,\quad \,\,\,B = \{ x:x$ is solution of ${x^2} + 5x + 6 = 0\} $
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