- Home
- Standard 11
- Mathematics
6.Permutation and Combination
medium
The number of ways in which $21$ identical apples can be distributed among three children such that each child gets at least $2$ apples, is
A
$406$
B
$130$
C
$142$
D
$136$
(JEE MAIN-2024)
Solution
After giving $2$ apples to each child $15$ apples left now $15$ apples can be distributed in ${ }^{15+3-1} \mathrm{C}_2={ }^{17} \mathrm{C}_2$ ways
$=\frac{17 \times 16}{2}=136$
Standard 11
Mathematics