Number of ways in which thirty five apples can be distributed among 3 boys so that each can have any

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6.Permutation and Combination

hard

The number of ways in which thirty five apples can be distributed among $3$ boys so that each can have any number of apples, is

A

$1332$

B

$666$

C

$333$

D

None of these

Solution

(b) The required number ${ = ^{3 + 35 – 1}}{C_{3 – 1}}{ = ^{37}}{C_2} = 666$

Aliter : The required number = coefficient of ${x^{35}}$ in ${(1 + x + {x^2} + …… + {x^{35}})^3}$.

Standard 11

Mathematics

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