7.Gravitation
medium

The orbital angular momentum of a satellite revolving at a distance $r$ from the centre is $L$. If the distance is increased to $16r$, then the new angular momentum will be

A

$16 L$

B

$64 L$

C

$\frac{L}{4}$

D

$4 L$

Solution

(d) $L = mvr = m\sqrt {\frac{{GM}}{r}r} = m\sqrt {GMr} $

$\therefore \,\,\,L \propto \sqrt r $

Standard 11
Physics

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