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7.Gravitation
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The orbital angular momentum of a satellite revolving at a distance $r$ from the centre is $L$. If the distance is increased to $16r$, then the new angular momentum will be
A
$16 L$
B
$64 L$
C
$\frac{L}{4}$
D
$4 L$
Solution
(d) $L = mvr = m\sqrt {\frac{{GM}}{r}r} = m\sqrt {GMr} $
$\therefore \,\,\,L \propto \sqrt r $
Standard 11
Physics
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