The period of oscillation of a simple pendulu | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) See the following force diagram. Vehicle is moving down the frictionless inclined surface so, it's acceleration is $g\sin 	heta $. Since vehi

Vedclass · Accepted Answer

$2\pi \sqrt {\frac{L}{{g\cos \alpha }}} $

Vedclass · Answer

(a) See the following force diagram. Vehicle is moving down the frictionless inclined surface so, it's acceleration is $g\sin 	heta $. Since vehicle is accelerating, a pseudo force $m(g\sin 	heta )$ will act on bob of pendulum which cancel the $\sin 	heta $ component of weight of the bob.

Hence net force on the bob is $F_{net}  = mg\cos 	heta $ or net acceleration of the bob is ${g_{eff}} = g\cos 	heta $

$	herefore $ Time period $T = 2\pi \sqrt {\frac{l}{{{g_{eff}}}}} = 2\pi \sqrt {\frac{l}{{g\cos 	heta }}} $

The period of oscillation of a simple pendulum of length $L$ suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination $\alpha$, is given by

Similar Questions

The ratio of frequencies of two pendulums are $2 : 3$, then their length are in ratio

Two pendulums begin to swing simultaneously. If the ratio of the frequency of oscillations of the two is $7 : 8$, then the ratio of lengths of the two pendulums will be

What is simple pendulum ? Deduce an expression for the time period of simple pendulum.

Two simple pendulums whose lengths are $100 cm$ and $121 cm$ are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum, will the two be in phase again

If the mass of a bob of a pendulum increased by $9$ times, the period of pendulum will ?