Position of a particle related to time is given by x =left(5 t ^2-4 t +5right) m . magnitude of velo

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2.Motion in Straight Line

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The position of a particle related to time is given by $x =\left(5 t ^2-4 t +5\right) m$. The magnitude of velocity of the particle at $t=2\,s$ will be $...........ms^{-1}$

A

$10$

B

$14$

C

$16$

D

$06$

(JEE MAIN-2023)

Solution

$x=5 t^2-4 t+5$

$v=10 t-4$

$\text { At } t=2 s \quad v=16\,m / s$

Standard 11

Physics

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