The positions of two cars $A$ and $B$ are $X_A = at + bt^2,$ $X_B = ft -t^2$ At what time Both cars will have same velocity
The positions of two cars $A$ and $B$ are $X_A = at + bt^2,$ $X_B = ft -t^2$ At what time Both cars will have same velocity
- A
$\frac{a+f}{2(1+b)}$
- B
$\frac{f-a}{2(1+b)}$
- C
$\frac{a-f}{1+b}$
- D
$\frac{a+f}{2(b-1)}$
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