A man walks on a straight road from his home to a market $2.5 \,km$ away with a speed of $5\, \,km/h$. Finding the market closed, he instantly turns and walks back home with a speed of $7.5 \,km/h$. The average speed of the man over the interval of time $0$ to $40 \,min$. is equal to
- A$5\, km/h$
- B$\frac{{25}}{4} \,km/h$
- C$\frac{{30}}{4} \,km/h$
- D$\frac{{45}}{8} \,km/h$
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