Gujarati
2. Electric Potential and Capacitance
easy

The potential at a point, due to a positive charge of $100\,\mu C$ at a distance of $9\,m$, is

A

${10^4}\,V$

B

${10^5}\,V$

C

${10^6}\,V$

D

${10^7}\,V$

Solution

(b) By using $V = 9 \times {10^9} \times \frac{Q}{r}$$ = 9 \times {10^9} \times \frac{{100 \times {{10}^{ – 6}}}}{9} = {10^5}\,V$

Standard 12
Physics

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