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- Standard 13
- Quantitative Aptitude
The price of an article is raised by $30 \%$ and then two successive discount of $10 \%$ each are allowed. Ultimately, the price of the article is
decreased by $5.3 \%$
increased by $3 \%$
increased by $5.3 \%$
increased by $10 \%$
Solution
Let the initial price of article be $\, 100.$
After $1st$ rise of $30 \%$, price $=1.3 \times 100=Rs. 130$
After $1$ st discount of $10 \%,$ price $=130\left(1-\frac{10}{100}\right)=Rs.117$
After $2nd$ discount of $10 \%,$ price $=117\left(1-\frac{10}{100}\right)=117 \times 0.9=Rs. 105.3$
$\therefore$ Price is increased by $5.3 \%$
Let the initial price of article be $Rs. 100$
$\therefore$ Marked price $=1.3 \times 100=₹ 130$
$\therefore$ Price after $2$ discounts of $10 \%$ each $=130\left\{1+\left(-10-10+\frac{10^{2}}{100}\right) \%\right\}$
$=130\left(\frac{100-19}{100}\right)=130 \times \frac{81}{100}=Rs. 105.3$
$\therefore$ $\%$ profit $=\frac{105.3-100}{100} \times 100=5.3 \%$
i.e. price is increased by $5.3 \%$
