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14.Probability
medium
The probability of $A, B, C$ solving a problem are $\frac{1}{3},\,\frac{2}{7},\,\frac{3}{8}$ respectively. If all the three try to solve the problem simultaneously, the probability that exactly one of them will solve it, is
A
$\frac{{25}}{{168}}$
B
$\frac{{25}}{{56}}$
C
$\frac{{20}}{{168}}$
D
$\frac{{30}}{{168}}$
Solution
(b) Here ${p_1} = \frac{1}{3},$ ${p_2} = \frac{2}{7}$ and ${p_3} = \frac{3}{8}$
$ \Rightarrow {q_1} = \frac{2}{3},$ ${q_2} = \frac{5}{7}$ and ${q_3} = \frac{5}{8}$
Required probability $ = {p_1}{q_2}{q_3} – {q_1}{p_2}{q_3} + {q_1}{q_2}{p_3}.$
Standard 11
Mathematics