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14.Probability
easy
The probability of getting a total of $5$ or $6$ in a single throw of $2$ dice is
A
$\frac{1}{2}$
B
$\frac{1}{4}$
C
$\frac{1}{3}$
D
$\frac{1}{6}$
Solution
(b) Total number of ways $ = 36$
Favourable numbers of cases are $(1\,\,4),\,(2,\,\,3),\,(3,\,\,2),$
$(4,\,\,1),\,(1,\,\,5),\,(2,\,\,4),\,(3,\,\,3),\,(4,\,\,2),\,(5,\,\,1) = 9$
Hence the required probability $ = \frac{9}{{36}} = \frac{1}{4}.$
Standard 11
Mathematics