Suppose that a die (with faces marked 1 to 6 ) is loaded in such a manner that for K = 1, 2, 3&helli

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14.Probability

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Suppose that a die (with faces marked $1$ to $6$) is loaded in such a manner that for $K = 1, 2, 3…., 6$, the probability of the face marked $K$ turning up when die is tossed is proportional to $K$. The probability of the event that the outcome of a toss of the die will be an even number is equal to

A

$\frac{1}{2}$

B

$\frac{4}{7}$

C

$\frac{2}{5}$

D

$\frac{1}{{21}}$

Solution

(a) Required probability $ = \frac{3}{6} = \frac{1}{2}$.

Standard 11

Mathematics

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