Probability of getting head and tail alternately in three throws of a coin (or a throw of three coin

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14.Probability

easy

The probability of getting head and tail alternately in three throws of a coin (or a throw of three coins), is

A

$\frac{1}{8}$

B

$\frac{1}{4}$

C

$\frac{1}{3}$

D

$\frac{3}{8}$

Solution

(b) Total probable ways $ = 8$

Favourable number of ways $ = [HTH,\,\,THT]$

Hence required probability $ = \frac{2}{8} = \frac{1}{4}.$

Standard 11

Mathematics

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