The proposition p Rightarrow ;sim (p; wedge s | vedclass

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Question

(d) 


	
		
			
			$p$
			
			
			$q$
			
			
			$\sim \,q$
			
			
			$p$ ⋀ $\sim \,q$
			
			
			$\sim (p$ ⋀ $\sim \,q)$

Vedclass · Accepted Answer

Neither $(a)$ nor $(b)$

Vedclass · Answer

(d) 


	
		
			
			$p$
			
			
			$q$
			
			
			$\sim \,q$
			
			
			$p$ ⋀ $\sim \,q$
			
			
			$\sim (p$ ⋀ $\sim \,q)$
			
			
			$p$ $\Rightarrow$ $\sim \,(p$ ⋀ $ \sim \, q) $
			
		
		
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
		
		
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
		
		
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
		
		
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$T$

			 
			
		
	


Result is neither tautology nor contradiction.

The proposition $p \Rightarrow \;\sim (p\; \wedge \sim \,q)$ is

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