Among the statements

$(S1)$: $(p \Rightarrow q) \vee((\sim p) \wedge q)$ is a tautology

$(S2)$: $(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)$ is a contradiction

  • [JEE MAIN 2023]
  • A

    neither $(S1)$ and $(S2)$ is True

  • B

    only $(S1)$ is True

  • C

    only $(S2)$ is True

  • D

    both $(S1)$ and $(S2)$ are True

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