Consider the two statements :

$(\mathrm{S} 1):(\mathrm{p} \rightarrow \mathrm{q}) \vee(\sim \mathrm{q} \rightarrow \mathrm{p})$ is a tautology

$(S2): (\mathrm{p} \wedge \sim \mathrm{q}) \wedge(\sim \mathrm{p} \vee \mathrm{q})$ is a fallacy.

Then :

$(p \to q) \leftrightarrow (q\ \vee  \sim p)$ is 

Statement$-I :$  $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim  q)\vee \sim  (p\vee \sim  q) .$
Statement$-II :$  $p\rightarrow (p\rightarrow q)$ is a tautology.

Consider the following three statements :

$(A)$ If $3+3=7$ then $4+3=8$.

$(B)$ If $5+3=8$ then earth is flat.

$(C)$ If both $(A)$ and $(B)$ are true then $5+6=17$. Then, which of the following statements is correct?

Consider

Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.

Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow   \sim  p )$  is a tautology.