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11.Dual Nature of Radiation and matter
medium
The radius of the orbital of electron in the hydrogen atom $0.5 \mathring A$. The speed of the electron is $2 \times {10^6}m/s$. Then the current in the loop due to the motion of the electron is ............. $mA$
A$1$
B$1.5 $
C$2.5 $
D$1.5 \times {10^{ - 2}}$
Solution
(a) Time period of revolution of electron $T = \frac{{2\pi }}{\omega } = \frac{{2\pi r}}{v}$
Hence corresponding electric current $i = \frac{e}{T} = \frac{{ev}}{{2\pi r}}$
$ \Rightarrow \,\,i = \frac{{1.6 \times {{10}^{ – 19}} \times 2 \times {{10}^6}}}{{2 \times 3.14 \times 0.5 \times {{10}^{ – 10}}}} = 1\,mA.$
Hence corresponding electric current $i = \frac{e}{T} = \frac{{ev}}{{2\pi r}}$
$ \Rightarrow \,\,i = \frac{{1.6 \times {{10}^{ – 19}} \times 2 \times {{10}^6}}}{{2 \times 3.14 \times 0.5 \times {{10}^{ – 10}}}} = 1\,mA.$
Standard 12
Physics
