The radius of the orbital of electron in the | vedclass

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Question

(a) Time period of revolution of electron $T = \frac{{2\pi }}{\omega } = \frac{{2\pi r}}{v}$
Hence corresponding electric current $i = \frac{e}{T} =

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(a) Time period of revolution of electron $T = \frac{{2\pi }}{\omega } = \frac{{2\pi r}}{v}$
Hence corresponding electric current $i = \frac{e}{T} = \frac{{ev}}{{2\pi r}}$
$ \Rightarrow \,\,i = \frac{{1.6 	imes {{10}^{ - 19}} 	imes 2 	imes {{10}^6}}}{{2 	imes 3.14 	imes 0.5 	imes {{10}^{ - 10}}}} = 1\,mA.$

The radius of the orbital of electron in the hydrogen atom $0.5 \mathring A$. The speed of the electron is $2 \times {10^6}m/s$. Then the current in the loop due to the motion of the electron is ............. $mA$

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