A water fountain on the ground sprinkles wate | vedclass

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Question

$\begin{array}{l}
Total\,area\,around\,fountain\
A = \pi R_{\max }^2 = \pi \frac{{{v^4}}}{{{g^2}}}\
\left[ {\,{R_{\max }} = \frac{{{v^2}\sin 2	h

Vedclass · Accepted Answer

$\;\frac{{\pi {v^4}}}{{{g^2}}}$

Vedclass · Answer

$\begin{array}{l}
Total\,area\,around\,fountain\
A = \pi R_{\max }^2 = \pi \frac{{{v^4}}}{{{g^2}}}\
\left[ {\,{R_{\max }} = \frac{{{v^2}\sin 2	heta }}{g} = \frac{{{v^2}\sin {{90}^ \circ }}}{g} = \frac{{{v^2}}}{g}} ight]
\end{array}$

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is $v$, the total area around the fountain that gets wet is :

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