The rate constant of esterification $(k) = k'\, [H_2O]$ rate constant of esterification $2.0\times 10^{-3}\,min^{-1}$ calculate  $k'$.

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$k=k^{\prime}\left[\mathrm{H}_{2} \mathrm{O}\right]$

$\begin{aligned} \therefore k^{\prime} =\frac{k}{\left[\mathrm{H}_{2} \mathrm{O}\right]}=\frac{2.0 \times 10^{-3} \mathrm{~min}^{-1}}{55.5 \mathrm{~mol} \mathrm{~L}^{-1}} \\ =0.036 \times 10^{-3} \mathrm{~mol}^{-1} \mathrm{~L} \mathrm{~min}^{-1} \\ =3.6 \times 10^{-5} \mathrm{~mol}^{-1} \mathrm{~L} \mathrm{~min}^{-1} \end{aligned}$

Similar Questions

During Kinetic study of reaction $2 A+B \rightarrow C+D$, the following results were obtained :

  $A[M]$ $B[M]$

initial rate of

formation of $D$

$i$ $0.1$ $0.1$ $6.0 \times 10^{-3}$
$ii$ $0.3$ $0.2$ $7.2 \times 10^{-2}$
$ii$ $0.3$ $0.4$ $2.88 \times 10^{-1}$
$iv$ $0.4$ $0.1$ $2.40 \times 10^{-2}$

Based on above data, overall order of the reaction is $\qquad$

  • [JEE MAIN 2024]

If the concentration of the reactants is increased, the rate of reaction

The concentration of $R$ in the reaction $R \rightarrow P$ was measured as a function of time and the following data is obtained:

$[R]$ (molar) $1.0$ $0.75$ $0.40$ $0.10$
$\mathrm{t}$ (min.) $0.0$ $0.05$ $0.12$ $0.18$

The order of the reaction is

  • [IIT 2010]

For reaction :

$2NO_2(g) + O_3(g) \to N_2O_5(g) + O_2(g)$

rate law is $R = K\, [NO_2]' [O_3]'$.

Which of these possible reaction mechanisms is consistent with the rate law?

Mechanism $I :$

$NO_2(g) + O_3(g) \to NO_3(g) + O_2(g)$ (slow)

$NO_3(g) + NO_2(g) \to N_2O_5(g)$ (fast)

Mechanism $II :$

$O_3(g)  \rightleftharpoons  O_2(g) + [O]$ (fast)

$NO_2(g) + [O] \to NO_3$ (slow)

$NO_3(g) + NO_2(g) \to  N_2O_5$ (fast)

The reaction between $A$ and $B$ is first order with respect to $A$ and zero order with respect to $B$. Fill in the blanks in the following table:

Experiment $[ A ] / mol\, ^{-1}$ $[ B ] / mol\, ^{-1}$ Initial rate $/$ $mol$ $L^{-1}$ $min$ $^{-1}$
$I$ $0.1$ $0.1$ $2.0 \times 10^{-2}$
$II$ - $0.2$ $4.0 \times 10^{-2}$
$III$ $0.4$ $0.4$ -
$IV$ - $0.2$ $2.0 \times 10^{-2}$