Gujarati
Hindi
10-2.Transmission of Heat
normal

The rate of emission of radiation of a black body at $273^o C$ is $E$, then the rate of emission of radiation of this body at $0^o C$ will be

A

$\frac{E}{{16}}$

B

$\frac{E}{{4}}$

C

$\frac{E}{{8}}$

D

$0$

Solution

$273^{\circ} \mathrm{C} \Rightarrow(273+273) k$

$0^{\circ} C \Rightarrow 273 k$

$E_{\mathrm{bb}_{1}}=\sigma A T_{1}^{4}$

$E_{\mathrm{bb}_{2}}=\sigma e A T_{2}^{4}$

$\frac{E_{1}}{E_{2}}=$ Ratio $=\left(\frac{T_{1}}{T_{2}}\right)^{4}$

$E_{2}=E_{1}\left(\frac{T_{2}}{T_{1}}\right)^{4}=E_{1}\left(\frac{273}{2 \times 273}\right)^{4}=\frac{E_{1}}{16}$

Standard 11
Physics

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