The ratio of specific charge of an alpha -pa | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) Specific charge $ = \frac{q}{m}$; Ratio $ = \frac{{{{\left( {\frac{q}{m}} \right)}_\alpha }}}{{{{\left( {\frac{q}{m}} \right)}_p}}} = \frac{{{q_\a

Vedclass · Accepted Answer

$1 : 2$

Vedclass · Answer

(c) Specific charge $ = \frac{q}{m}$; Ratio $ = \frac{{{{\left( {\frac{q}{m}} ight)}_\alpha }}}{{{{\left( {\frac{q}{m}} ight)}_p}}} = \frac{{{q_\alpha }}}{{{q_p}}} 	imes \frac{{{m_p}}}{{{m_\alpha }}} = \frac{1}{2}$.

The ratio of specific charge of an $\alpha $ -particle to that of a proton is

Similar Questions

An electron is accelerated through a potential difference of $200$ volts. If $e/m$ for the electron be $1.6 \times {10^{11}}$ $coulomb/kg$ , the velocity acquired by the electron will be

In an electron gun, the electrons are accelerated by the potential $V$. If e is the charge and $m$ is the mass of an electron, then the maximum velocity of these electrons will be

Which of the following have highest specific charge

$n$ Millikan oil drop experiment, a charged drop of mass $1.8 \times {10^{ - 14}}kg $ is stationary between its plates. The distance between its plates is $0.90 cm$ and potential difference is $2.0$ kilo volts. The number of electrons on the drop is

In Milikan’s experiment, an oil drop having charge $q$ gets stationary on applying a potential difference $V$ in between two plates separated by a distance $‘d’$. The weight of the drop is