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11.Dual Nature of Radiation and matter
medium
The ratio of specific charge of an $\alpha $ -particle to that of a proton is
A
$2 : 1 $
B
$1 : 1$
C
$1 : 2$
D
$1 : 3$
Solution
(c) Specific charge $ = \frac{q}{m}$; Ratio $ = \frac{{{{\left( {\frac{q}{m}} \right)}_\alpha }}}{{{{\left( {\frac{q}{m}} \right)}_p}}} = \frac{{{q_\alpha }}}{{{q_p}}} \times \frac{{{m_p}}}{{{m_\alpha }}} = \frac{1}{2}$.
Standard 12
Physics
