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11.Dual Nature of Radiation and matter
easy
Three particles having their charges in the ratio of $1 : 3 : 5$ produce the same spot on the screen in Thomson’s experiment. Their masses are in the ratio of
A
$5 : 3 : 1$
B
$3 : 1 : 5$
C
$1 : 3 : 5$
D
$5 : 1 : 3$
Solution
(c) Since spot is same, hence $\frac{e}{m}$ should be same i.e.,
As $q_1 : q_2 : q_3 = 1 : 3 : 5$. Hence $m_1 : m_2 : m_3 = 1 : 3 : 5$
Standard 12
Physics
