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11.Dual Nature of Radiation and matter
easy
The ratio of the energy of a photon with $\lambda = 150\,nm$ to that with $\lambda = 300\,nm$ is
A
$2$
B
$1/4$
C
$4$
D
$1/2$
Solution
(a) $E = \frac{{hc}}{\lambda }$
$\Rightarrow \frac{{{E_1}}}{{{E_2}}} = \frac{{300}}{{150}} = \frac{2}{1}$
Standard 12
Physics
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