The reaction of $\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3} \mathrm{Cl}_{3}$ $(A)$ with $\mathrm{LiBH}_{4}$ in tetrahydrofurane gives inorganic benzene $(B)$. Further, the reaction of $(A)$ with $(C)$ leads to $\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3}(\mathrm{Me})_{3}$. than Compounds $(\mathrm{B})$ and $(\mathrm{C})$ respectively, are

  • [JEE MAIN 2020]
  • A

    Boron nitride and $MeBr$

  • B

    Borazine and $MeMgBr$

  • C

    Borazine and $MeBr$

  • D

    Diborane and $MeMgBr$

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