1.Units, Dimensions and Measurement
medium

The resistance $R =\frac{ V }{ I },$ where $V =(50 \pm 2) \;V$ and $I=(20 \pm 0.2)\;A.$ The percentage error in $R$ is $x\%$. The value of $x$ to the nearest integer is .........

A

$3$

B

$6$

C

$7$

D

$5$

(JEE MAIN-2021)

Solution

$\frac{\Delta R }{ R } \times 100=\frac{\Delta V }{ V } \times 100+\frac{\Delta I }{ I } \times 100$

$\%$ error in $R =\frac{2}{50} \times 100+\frac{0.2}{20} \times 100$

$\%$ error in $R =4+1$

$\%$ error in $R =5 \%$

Standard 11
Physics

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