Result after adding 3.8 × 10^{-6} with 4.2 × 10^{-5} with due regard to significant figures is

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1.Units, Dimensions and Measurement

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The result after adding $3.8 \times 10^{-6}$ with $4.2 \times 10^{-5}$ with due regard to significant figures is

A$4.58 \times {10^{ - 5}}$

B$0.458 \times {10^{ -4 }}$

C$4.6 \times {10^{ - 5}}$

D$45.8 \times {10^{ - 6}}$

Solution

$3.8 \times 10^{-6}+42.0 \times 10^{-6}=45.8 \times 10^{-6}$
$=4.6 \times 10^{-5}$
Significant figure after decimal should be equal to one.

Standard 11

Physics

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