Dimension of frac{1}{2} {varepsilon _0}{E^2}({varepsilon _0} : permittivity of free space; E : elect

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1.Units, Dimensions and Measurement

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The dimension of $\frac{1}{2}$${\varepsilon _0}{E^2}({\varepsilon _0}$: permittivity of free space; $E$: electric field) is

A

$ML{T^{^{ - 1}}}$

B

$M{L^2}{T^{ - 2}}$

C

$M{L^{ - 1}}{T^{ - 2}}$

D

$M{L^2}{T^{ - 1}}$

Solution

(c) Energy density $ = \frac{{{\rm{Energy}}}}{{{\rm{Volume}}}}$ so it’s dimensions are $\frac{{M{L^2}{T^{ – 2}}}}{{{L^3}}} = [M{L^{ – 1}}{T^{ – 2}}]$

Standard 11

Physics

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