Gujarati
3-1.Vectors
medium

The resultant of the two vectors having magnitude $2$ and $3$ is $1$. What is their cross product

A

$6$

B

$3$

C

$1$

D

$0$

Solution

(d) $\sqrt {{2^2} + {3^2} + 2 \times 2 \times 3 \times \cos \theta } = 1$

By solving we get $\theta = 180^\circ $

$⇒$ $\vec A \times \vec B = 0$

Standard 11
Physics

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