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3-1.Vectors
medium
The resultant of the two vectors having magnitude $2$ and $3$ is $1$. What is their cross product
A
$6$
B
$3$
C
$1$
D
$0$
Solution
(d) $\sqrt {{2^2} + {3^2} + 2 \times 2 \times 3 \times \cos \theta } = 1$
By solving we get $\theta = 180^\circ $
$⇒$ $\vec A \times \vec B = 0$
Standard 11
Physics