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10-1.Thermometry, Thermal Expansion and Calorimetry
easy
The scale on a steel metre stick is calibrated at $20^o\,C$.The error in the reading of $50\,cm$ at $30^o\,C$ is: (take linear expansion coefficient of steel $= 1.0 \times 10^{-5} / ^oC)$
A
$10^{-3} \,cm$
B
$2 \times 10^{-3} \,cm$
C
$5 \times 10^{-3} \,cm$
D
$10^{-2} \,cm$
Solution
$\Delta \mathrm{L}=\mathrm{L}_{\mathrm{o}} \alpha \Delta \mathrm{t}$
$=(50 \mathrm{cm})\left(1.0 \times 10^{-5}/^{\circ}{C}\right)(30-20)^{\circ} \mathrm{C}$
$=5 \times 10^{-3} \mathrm{cm}$
Standard 11
Physics
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