Gujarati
Hindi
10-1.Thermometry, Thermal Expansion and Calorimetry
easy

The scale on a steel metre stick is calibrated at $20^o\,C$.The error in the reading of $50\,cm$ at $30^o\,C$ is: (take linear expansion coefficient of steel $= 1.0 \times 10^{-5} /  ^oC)$

A

$10^{-3} \,cm$

B

$2 \times 10^{-3} \,cm$

C

$5 \times 10^{-3} \,cm$

D

$10^{-2} \,cm$

Solution

$\Delta \mathrm{L}=\mathrm{L}_{\mathrm{o}} \alpha \Delta \mathrm{t}$

$=(50 \mathrm{cm})\left(1.0 \times 10^{-5}/^{\circ}{C}\right)(30-20)^{\circ} \mathrm{C}$

$=5 \times 10^{-3} \mathrm{cm}$

Standard 11
Physics

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