Simple interest accrued on an amount of Rs. 19800 at end of 3 years is Rs. 7128 . What would be comp

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6.Interest

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The simple interest accrued on an amount of $Rs. 19800$ at the end of $3$ years is $Rs. 7128$. What would be the compound interest (In $Rs.$) accrued on the same amount at the same rate in the same period?

A

$8934.6784$

B

$8017.5744$

C

$7861.8754$

D

$6871.6734$

Solution

Initially the SI was Rs. 7128

$\Rightarrow SI =\frac{ P \times R \times T }{100} \Rightarrow 7128=\frac{19800 \times R \times 3}{100}$

$\Rightarrow R=12 \%$

$\Rightarrow \quad C I=P\left[\left(1+\frac{R}{100}\right)^{T}-1\right]$

$=19800\left[\left(1+\frac{12}{100}\right)^{3}-1\right]$ (Time $=3$ years

$=19800\left[(1.12)^{3}-1\right]=19800[1.4049-1]$

$= Rs .8017 .5744$

Standard 13

Quantitative Aptitude

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