Solubility of PbI₂ at 25,^oC is 0.7, g, L^{-1} . solubility product of PbI₂ at this temperature

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6-2.Equilibrium-II (Ionic Equilibrium)

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The solubility of $PbI_2$ at $25\,^oC$ is $0.7\, g\, L^{-1}$ . The solubility product of $PbI_2$ at this temperature is (molar mass of $PbI_2\, = 461.2\, g\, mol^{-1}$ )

A

$1.40\times10^{-9}$

B

$0.14\times10^{-9}$

C

$140\times10^{-9}$

D

$14.0\times10^{-9}$

(AIEEE-2012)

Solution

$PbC{l_2} \rightleftharpoons \mathop {P{b^{ + + }}}\limits_s + \mathop {2{I^ – }}\limits_{2s} $

${K_{sp}} = s \times {(2s)^2} = 4{s^3}$

$ = 4 \times {\left( {\frac{{0.7}}{{461.2}}} \right)^3} = 14.0 \times {10^{ – 9}}$

Standard 11

Chemistry

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