Why only As^{3+} gets precipitated as As₂S₃ and not Zn^{2+} as ZnS when H₂S is passed through

English

Gujarati

Hindi

6-2.Equilibrium-II (Ionic Equilibrium)

medium

Why only $As^{3+}$ gets precipitated as $As_2S_3$ and not $Zn^{2+}$ as $ZnS$ when $H_2S$ is passed through an acidic solution containing $As^{3+}$ and $Zn^{2+}$?

A

Solubility product of $As_2S_3$ is less than that of $ZnS$

B

Enough $As^{3+}$ are present in acidic medium

C

Zinc salt does not ionise in acidic medium

D

Solubility product changes in presence of an acid

(AIIMS-2013)

Solution

$K_{sp}$ of $As_2S_3$ is less than $ZnS$. In acid medium ionisation of $H_2S$ is suppresed (common ion effect) and $K_{sp}$ of $ZnS$ does not exceed.

Standard 11

Chemistry

Share

Similar Questions

What is the minimum concentration of $SO_4^{2 – }$ required to precipitate $BaS{O_4}$ in a solution containing $1.0 \times {10^{ – 4}}\,mol\,\,\,B{a^{2 + }}$ (${K_{sp}}$ for $BaS{O_4}$ is $4 \times {10^{ – 10}}$)

medium

If this is passed in solution of $0.1$ $M$ $Zn^{2+}$ and $0.01$ $M$ $Cu^{+}$ and concentration of ${S^{2 – }}$ made $8.1 \times {10^{ – 31}}$ $M$. Precipitation of $ZnS$ and $CuS$ will take place ? ${K_{sp}}$ of $\left( {ZnS} \right) = 3.0 \times {10^{ – 23}}$ and ${K_{sp}}$ of $\left( {CuS} \right) = 8.0 \times {10^{ – 34}}$

hard

The values of $K_{ sp }$ of two sparingly soluble salts $Ni ( OH )_{2}$ and $AgCN$ are $2.0 \times 10^{-15}$ and $6 \times 0^{-17}$ respectively. Which salt is more soluble? Explain.

medium

The solubility of $PbI_2$ at $25\,^oC$ is $0.7\, g\, L^{-1}$ . The solubility product of $PbI_2$ at this temperature is (molar mass of $PbI_2\, = 461.2\, g\, mol^{-1}$ )

hard

(AIEEE-2012)

The solubility product of a salt having general formula $M{X_2},$ in water is : $4 \times {10^{ – 12}}$. The concentration of ${M^{2 + }}$ ions in the aqueous solution of the salt is

medium

(AIEEE-2005)