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$0.2\,\,M\,\,NaCl$ विलयन में $AgCl$ की विलेयता होगी $(AgCl$ के लिए ${K_{sp}}$$ = 1.20 \times {10^{ - 10}})$
$0.2\,\,M$
$1.2 \times {10^{ - 10}}\,M$
$0.2 \times {10^{ - 10}}\,M$
$0.2 \times {10^{ - 10}}\,M$
Solution
(d) $\mathop {AgCl}\limits_a \rightleftharpoons \mathop {A{g^ + }}\limits_a + \mathop {C{l^ – }}\limits_a $
$\mathop {NaCl}\limits_{0.02} $ $ \rightleftharpoons $ $\mathop {N{a^ + }}\limits_{0.02\,\,\,\,\,} \,\, + \mathop {C{l^ – }}\limits_{0.02\,\,\,\,\,\,} $
${K_{sp}}\,\,AgCl = 1.20 \times {10^{ – 10}}$
${K_{sp}}\,\,AgCl = [A{g^ + }]\,\,[C{l^ – }]$$ = a \times [a + 0.2]$ $ = {a^2} + 0.2a$
${a^2}$ बहुत कम है इसलिए इसे नगण्य मान सकते हैं
${K_{sp}}\,\,AgCl = 0.2a$
$1.20 \times {10^{ – 10}} = 0.2a$
$a = \frac{{1.20 \times {{10}^{ – 10}}}}{{0.20}} = 6 \times {10^{ – 10}}$ मोल
