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6-2.Equilibrium-II (Ionic Equilibrium)
medium
The solubility of $CuBr$ is $2 \times {10^{ - 4}}\,mol/l$ at $25\,^oC$. The ${K_{sp}}$ value for $CuBr$ is
A
$4 \times {10^{ - 8}}\,mo{l^2}\,{l^{ - 2}}$
B
$4 \times {10^{ - 11}}\,mo{l^2}\,{l^{ - 1}}$
C
$4 \times {10^{ - 4}}\,mo{l^2}\,{l^{ - 2}}$
D
$4 \times {10^{ - 15}}\,mo{l^2}\,{l^{ - 2}}$
(AIIMS-2002)
Solution
(a) $\mathop {CuBr}\limits_{{K_{sp}}} \rightleftharpoons \mathop {C{u^ + }}\limits_{(S)\,\,} + \mathop {B{r^ – }}\limits_{(S)\,\,\,\,} $
${K_{sp}} = {S^2} = {(2 \times {10^{ – 4}})^2} = 4 \times {10^{ – 8}}\,\frac{{mo{l^2}}}{{{l^2}}}$
Standard 11
Chemistry
