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6-2.Equilibrium-II (Ionic Equilibrium)
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The solubility product of a sparingly soluble salt $AB$ at room temperature is $1.21 \times {10^{ - 6}}$. Its molar solubility is
A
$1.21 \times {10^{ - 6}}$
B
$1.21 \times {10^{ - 3}}$
C
$1.1 \times {10^{ - 4}}$
D
$1.1 \times {10^{ - 3}}$
Solution
(d) $AB $ is a binary electrolyte.
$S = \sqrt {{K_{sp}}} = \sqrt {1.21 \times {{10}^{ – 6}}} = 1.1 \times {10^{ – 3}}M$
Standard 11
Chemistry
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