Gujarati
6-2.Equilibrium-II (Ionic Equilibrium)
medium

The solubility product of a sparingly soluble salt $AB$ at room temperature is $1.21 \times {10^{ - 6}}$. Its molar solubility is

A

$1.21 \times {10^{ - 6}}$

B

$1.21 \times {10^{ - 3}}$

C

$1.1 \times {10^{ - 4}}$

D

$1.1 \times {10^{ - 3}}$

Solution

(d) $AB $ is a binary electrolyte.

$S = \sqrt {{K_{sp}}} = \sqrt {1.21 \times {{10}^{ – 6}}} = 1.1 \times {10^{ – 3}}M$

Standard 11
Chemistry

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