Solubility product of magnesium hydroxide Mg{left( {OH} right)₂} is 1.2 × {10^{ - 11}} . Calculat

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6-2.Equilibrium-II (Ionic Equilibrium)

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The solubility product of magnesium hydroxide $Mg{\left( {OH} \right)_2}$ is $1.2 \times {10^{ - 11}}$. Calculate its solubility in pure water and $0.05$ $M$ $NaOH$.

Option A

Option B

Option C

Option D

Solution

$1.44 \times 10^{-4}$ mol $L^{-1}$ water solubility and $5.0 \times 10^{-9}$ mol $L^{-1}$ solubility in $\mathrm{NaOH}$

Standard 11

Chemistry

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