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4.Chemical Bonding and Molecular Structure
hard
The species having bond order different from that in $CO$ is
A
$NO^-$
B
$NO^+$
C
$CN^-$
D
$N_2$
Solution
$CO$ contains $14$ electrons ( $6$ from carbon and $8$ from oxygen).
$NO ^{-}$contains $16$ electrons ( $7$ from nitrogen, $8$ from oxygen, add $1$ more for negative charge).
$NO ^{+}$has $14$ electrons ( $7$ from nitrogen, $8$ from oxygen, subtract $1$ for positive charge).
$CN ^{-1}$ has $14$ electrons ( $7$ from nitrogen, $6$ from carbon, add $1$ more for negative charge).
$N _2$ has $14$ electrons ( $7$ from nitrogen each).
The species containing the same number of electrons have the same bond order.
So $NO ^{-}$is the only one which has bond order different. So option $A$ is correct.
Standard 11
Chemistry
