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The species having bond order different from that in $CO$ is
$NO^-$
$NO^+$
$CN^-$
$N_2$
Solution
$CO$ contains $14$ electrons ( $6$ from carbon and $8$ from oxygen).
$NO ^{-}$contains $16$ electrons ( $7$ from nitrogen, $8$ from oxygen, add $1$ more for negative charge).
$NO ^{+}$has $14$ electrons ( $7$ from nitrogen, $8$ from oxygen, subtract $1$ for positive charge).
$CN ^{-1}$ has $14$ electrons ( $7$ from nitrogen, $6$ from carbon, add $1$ more for negative charge).
$N _2$ has $14$ electrons ( $7$ from nitrogen each).
The species containing the same number of electrons have the same bond order.
So $NO ^{-}$is the only one which has bond order different. So option $A$ is correct.
Similar Questions
Match List $I$ with List $II$ :
|
List $I$ (Molecule Species) |
List $I$ ( Property Shape ) |
| $A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ | $I$ Paramagnetic |
| $B$ $NO$ | $II$ Diamagnetic |
| $C$ $\mathrm{NO}_2^{-}$ | $III$ Tetrahedral |
| $D$ $\mathrm{I}_3^{-}$ | $IV$ Linear |
Choose the correct answer from the options given below :
