The square root of sqrt {(50)} + sqrt {(48)} | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d) $\sqrt {(50)} + \sqrt {(48)} $= $\sqrt 2 {(\sqrt 3 + \sqrt 2 )^2}$;

$	herefore \sqrt {\sqrt {50} + \sqrt {48} } = {2^{1/4}}(\sqrt 3 + \sqrt 2

Vedclass · Accepted Answer

${2^{1/4}}(\sqrt 3 + \sqrt 2 )$

Vedclass · Answer

(d) $\sqrt {(50)} + \sqrt {(48)} $= $\sqrt 2 {(\sqrt 3 + \sqrt 2 )^2}$;

$	herefore \sqrt {\sqrt {50} + \sqrt {48} } = {2^{1/4}}(\sqrt 3 + \sqrt 2 )$.

The square root of $\sqrt {(50)} + \sqrt {(48)} $ is

Similar Questions

If ${a^{1/x}} = {b^{1/y}} = {c^{1/z}}$ and ${b^2} = ac$ then $x + z = $

Solution of the equation $\sqrt {(x + 10)} + \sqrt {(x - 2)} = 6$ are

If ${a^x} = bc,{b^y} = ca,\,{c^z} = ab,$ then $xyz$=

${a^{m{{\log }_a}n}} = $

The cube root of $9\sqrt 3 + 11\sqrt 2 $ is