${4 \over {1 + \sqrt 2 - \sqrt 3 }} = $
$2 + \sqrt 2 + \sqrt 6 $
$1 + \sqrt 2 + \sqrt 3 $
$3 + \sqrt 2 + \sqrt 3 $
None of these
$\root 4 \of {(17 + 12\sqrt 2 )} = $
If ${a^x} = {(x + y + z)^y},{a^y} = {(x + y + z)^z}$, ${a^z} = {(x + y + z)^x},$ then
${{{{[4 + \sqrt {(15)} ]}^{3/2}} + {{[4 - \sqrt {(15)} ]}^{3/2}}} \over {{{[6 + \sqrt {(35)} ]}^{3/2}} - {{[6 - \sqrt {(35)} ]}^{3/2}}}} = $
If ${x^y} = {y^x},$then ${(x/y)^{(x/y)}} = {x^{(x/y) - k}},$ where $k = $
If $x = {2^{1/3}} - {2^{ - 1/3}},$ then $2{x^3} + 6x = $