4-1.Complex numbers
hard

જેના માટે $\frac{1+i \cos \theta}{1-2 i \cos \theta}$ શુદ્ધ કાલ્પનિક હોય, તેવી $\theta \in[-\pi, 2 \pi]$ ની તમામ શક્ય કિંમતોનો સરવાળો .......... છે. 

A

$2 \pi$

B

$3 \pi$

C

$5 \pi$

D

$4 \pi$

(JEE MAIN-2024)

Solution

$ Z=\frac{1+i \cos \theta}{1-2 i \cos \theta} $

$ Z=-\bar{Z} \Rightarrow \frac{1+i \cos \theta}{1-2 i \cos \theta}=-\left(\frac{\overline{1+i \cos \theta}}{1-2 i \cos \theta}\right) $

$ (1+i \cos \theta)(\overline{1-2 i \cos \theta})=-(1-2 i \cos \theta)(\overline{1+i \cos \theta}) $

$ (1+i \cos \theta)(1+2 i \cos \theta)=-(1-2 i \cos \theta)(1-i \cos \theta) $

$ 1+3 i \cos \theta-2 \cos ^2 \theta=-\left(1-3 i \cos \theta-2 \cos ^2 \theta\right) $

$ 2-4 \cos ^2 \theta=0 $

$ \Rightarrow \cos ^2 \theta=\frac{1}{2} \Rightarrow \theta=-\frac{\pi}{4},-\frac{3 \pi}{4}, \frac{\pi}{4}, \frac{3 \pi}{4}, \frac{5 \pi}{4}, \frac{7 \pi}{4} $

$ \text { sum }=3 \pi$

Standard 11
Mathematics

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