Sum of five consecutive integers is a and sum of next five consecutive integers is b . Then frac{(b-

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The sum of five consecutive integers is $a$ and the sum of next five consecutive integers is $b$. Then $\frac{(b-a)}{100}$ is equal to

A

$\frac{1}{4}$

B

$\frac{1}{2}$

C

$3$

D

$2$

Solution

Third number = average of the five consecutive numbers $=\frac{a}{5}$

First number of next sequence $=\frac{a}{5}+3$

Now, according to the question,

$\therefore \frac{a}{5}+3+\frac{a}{5}+4+\frac{a}{5}+5+\frac{a}{5}+6+\frac{a}{5}+7=b$

$\Rightarrow a+25=b$

$\Rightarrow 25=b-a$

$\therefore \frac{b-a}{100}=\frac{25}{100}=\frac{1}{4}$

Standard 13

Quantitative Aptitude

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