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4.Average
medium
The sum of five consecutive integers is $a$ and the sum of next five consecutive integers is $b$. Then $\frac{(b-a)}{100}$ is equal to
A
$\frac{1}{4}$
B
$\frac{1}{2}$
C
$3$
D
$2$
Solution
Third number = average of the five consecutive numbers $=\frac{a}{5}$
First number of next sequence $=\frac{a}{5}+3$
Now, according to the question,
$\therefore \frac{a}{5}+3+\frac{a}{5}+4+\frac{a}{5}+5+\frac{a}{5}+6+\frac{a}{5}+7=b$
$\Rightarrow a+25=b$
$\Rightarrow 25=b-a$
$\therefore \frac{b-a}{100}=\frac{25}{100}=\frac{1}{4}$
Standard 13
Quantitative Aptitude
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