Temperature of a wire of length 1 metre and area of cross-section 1,c{m^2} is increased from 0°C

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8.Mechanical Properties of Solids

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The temperature of a wire of length $1$ metre and area of cross-section $1\,c{m^2}$ is increased from $0°C$ to $100°C$. If the rod is not allowed to increase in length, the force required will be $(\alpha = {10^{ - 5}}/^\circ C$ and $Y = {10^{11}}\,N/{m^2})$

A

${10^3}N$

B

${10^4}N$

C

${10^5}N$

D

${10^9}N$

Solution

(b) $F = $force developed$ = YA\alpha (\Delta \theta )$

$ = {10^{11}} \times {10^{ – 4}} \times {10^{ – 5}} \times 100 = {10^4}N$

Standard 11

Physics

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