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8.Mechanical Properties of Solids
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The temperature of a wire of length $1$ metre and area of cross-section $1\,c{m^2}$ is increased from $0°C$ to $100°C$. If the rod is not allowed to increase in length, the force required will be $(\alpha = {10^{ - 5}}/^\circ C$ and $Y = {10^{11}}\,N/{m^2})$
A
${10^3}N$
B
${10^4}N$
C
${10^5}N$
D
${10^9}N$
Solution
(b) $F = $force developed$ = YA\alpha (\Delta \theta )$
$ = {10^{11}} \times {10^{ – 4}} \times {10^{ – 5}} \times 100 = {10^4}N$
Standard 11
Physics
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