The third term of a $G.P.$ is the square of first term. If the second term is $8$, then the ${6^{th}}$ term is
$120$
$124$
$128$
$132$
The sum of the first $n$ terms of the series $\frac{1}{2} + \frac{3}{4} + \frac{7}{8} + \frac{{15}}{{16}} + .........$ is
The G.M. of the numbers $3,\,{3^2},\,{3^3},\,......,\,{3^n}$ is
The product of three geometric means between $4$ and $\frac{1}{4}$ will be
Find the value of $n$ so that $\frac{a^{n+1}+b^{n+1}}{a^{n}+b^{n}}$ may be the geometric mean between $a$ and $b .$
If ${p^{th}},\;{q^{th}},\;{r^{th}}$ and ${s^{th}}$ terms of an $A.P.$ be in $G.P.$, then $(p - q),\;(q - r),\;(r - s)$ will be in