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8. Sequences and Series
easy
The third term of a $G.P.$ is the square of first term. If the second term is $8$, then the ${6^{th}}$ term is
A
$120$
B
$124$
C
$128$
D
$132$
Solution
(c) ${a^2} = a{r^2}$
$ \Rightarrow $ $a = {r^2}$. Also $ar = 8$
$ \Rightarrow $ $r = 2$ and $a = 4$.
$\therefore $ ${T_6} = a{r^5} = 4 \times {2^5} = 128$.
Standard 11
Mathematics