Time period of a satellite of earth is 5 hours. If separation between earth and satellite is increas

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7.Gravitation

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The time period of a satellite of earth is $5$ hours. If the separation between the earth and the satellite is increased to four times the previous value, the new time period will become ......... $hours$

A

$20$

B

$10$

C

$80$

D

$40$

(AIEEE-2003) (AIIMS-1995)

Solution

(d) ${T_2} = {T_1}{\left( {\frac{{{R_2}}}{{{R_1}}}} \right)^{3/2}} = {T_1}{(4)^{3/2}} = 8{T_1} = 40\,hr$

Standard 11

Physics

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