Time period of a vibration magnetometer is T_0 . Its magnet is replaced by another magnet whose mome

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5.Magnetism and Matter

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The time period of a vibration magnetometer is $T_0$. Its magnet is replaced by another magnet whose moment of inertia is $3$ $times$ and magnetic moment is $1/3$ of the initial magnet. The time period now will be

A

$3T_0$

B

$T_0$

C

${T_0}/\sqrt 3 $

D

$T_0/3$

Solution

(a)$T = 2\pi \sqrt {\frac{I}{{M{B_H}}}} ;\;I \to 3$ $times$ and $M \to \frac{1}{3}$ $times$
So $T \to 3$ $times$ i.e. $T' = 3{T_0}$

Standard 12

Physics

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