Time period of oscillation of a bar magnet suspended horizontally along magnetic meridian is T_0 . I

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5.Magnetism and Matter

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The time period of oscillation of a bar magnet suspended horizontally along the magnetic meridian is $T_0$. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be

A

$\frac{{{T_0}}}{2}$

B

$\frac{{{T_0}}}{{\sqrt 2 }}$

C

$\sqrt 2 {T_0}$

D

$2{T_0}$

Solution

(c)$T = 2\pi \sqrt {\frac{I}{{M{B_H}}}} \Rightarrow T \propto \sqrt I \propto \sqrt {\rm{w}} \Rightarrow T' = \sqrt 2 \;{T_0}$

Standard 12

Physics

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