The type of hybridisation of boron in diborane is
$s p$
$s p^{2}$
$s p^{3}$
$d s p^{2}$
$(c)$ Boron in diborane is $s p^{3}$ hybridised.
The ionic carbide is
$H_3BO_3$ $\xrightarrow{{{T_1}}}X\xrightarrow{{{T_2}}}Y\xrightarrow{{red\,hot}}$ $B_2O_3$
if $T_1 < T_2$ then $X$ and $Y$ respectively are
Choose the correct sequence for the geometry of the given molecules Borazone, Borazole, $B_3O_6^{-3}$ , $Fe_2Cl_6$, trimer of $FCN$. [$'P'$ stands for planar and $'NP'$ stands for non-planar]
$B{\left( {OH} \right)_3} + NaOH \to NaB{O_2} + Na\left[ {B{{\left( {OH} \right)}_4}} \right] + {H_2}O$
How can this reaction is made to proceed in forward direction?
Mention isotops of boron.
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